Persisting 2 Tabelle mit demselben erzeugt id

Question

Ich versuche, eine übergeordnete Entität zu bestehen, die mit einer anderen Kind Einheit verbunden ist, aber das Problem ist, dass die ID nicht für dieses Kind wird erzeugt, wenn persistierende so dass ich diesen Fehler habe: [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] ORA-01400: cannot insert NULL into ("L2S$OWNER"."SABRI"."TRANSITION_MATRIX_ID")

gibt es das Kind Entity:

@Data 
@Entity 
@IdClass(MyLibrarySabriEntityPK.class) 
@Table(name = "SABRI", schema = "L2S$OWNER", catalog = "") 

public class MyLibrarySabriEntity extends ActionForm { 
@Access(AccessType.FIELD) 
@Id 
@ManyToOne 
@JoinColumn(name = "TRANSITION_MATRIX_ID", referencedColumnName = "ID_TRANSITION_MATRIX") 
private MyLibraryTestEntity sabriEntity; 

@Id 
private String RATING_ID_ROW; 

@Id 
private String RATING_ID_COL; 


@Basic 
@Column(name = "TRANSITION_PROBABILITY", nullable = true, insertable = true, updatable = true, precision = 20) 
private Double TRANSITION_PROBABILITY;} 

die PK-Klasse:

@Data 
public class MyLibrarySabriEntityPK implements Serializable { 
private String TRANSITION_MATRIX_ID; 
private String RATING_ID_ROW; 
private String RATING_ID_COL; 


public MyLibrarySabriEntityPK(String TRANSITION_MATRIX_ID,String RATING_ID_COL,String RATING_ID_ROW){ 
    this.TRANSITION_MATRIX_ID=TRANSITION_MATRIX_ID; 
    this.RATING_ID_COL = RATING_ID_COL; 
    this.RATING_ID_ROW= RATING_ID_ROW; 
} 

}

ist das Mutterunternehmen:

@Data 
@Entity 
@Table(name = "TEST", schema = "L2S$OWNER", catalog = "") 
public class MyLibraryTestEntity extends ActionForm { 

    @Access(AccessType.FIELD) 
    @OneToMany(mappedBy = "sabriEntity", cascade = CascadeType.PERSIST) 
    private final List<MyLibrarySabriEntity> entities = new ArrayList<MyLibrarySabriEntity>(25); 

    public void addEntitysabri(MyLibrarySabriEntity entity) { 
     getEntities().add(entity); 
     entity.setSabriEntity(this); 
    } 

    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO, generator = "IdGenerated") 
    @GenericGenerator(name = "IdGenerated", strategy = "dao.Identifier") 
    @Column(name = "ID_TRANSITION_MATRIX", nullable = false, insertable = false, updatable = false, length = 10) 
    private String ID_TRANSITION_MATRIX; 


    @Basic 
    @Column(name = "REFERENCE", nullable = true, insertable = true, updatable = true, precision = 0) 
    private Integer reference;} 

Und hier versuche ich, die übergeordnete Tabelle zu bestehen, die auch die untergeordnete Tabelle bestehen bleiben soll, aber die Id nicht erzeugt wird!

MyLibrarySabriEntity Entity = null; 
MyLibraryTestEntity test = getMyLibraryTestEntity(matrixStartDate, matrixName); // here I get the values of my entity test (parent) 
    try { 
     transaction.begin(); 
     for (int row = 0; row < 20; row++) { 
      for (int col = 0; col < 20; col++) { 
       double val = cells.get(row + FIRST_ROW, col + FIRST_COL).getDoubleValue(); 
       Entity = getMyLibrarySabriEntity(col, row, val); // this get the values of the Entity parameters (child) 
       Entity.setSabriEntity(test); 
       test.addEntitysabri(Entity); 
       em.persist(test); 
      } 
     } 


    } catch (Exception e) { 
     if (transaction.isActive()) 
      transaction.rollback(); 
     LOGGER.warn(e.getMessage(), e); 

    } finally { 
     if (transaction.isActive()) 
      transaction.commit(); 
     em.close(); 

    } 

Answer 1

Sie Unter der Annahme, verwenden JPA 2.0+

diese Zuordnung vollständig entfernen:

@Id 
@Column(name = "TRANSITION_MATRIX_ID", nullable = false, 
     insertable = true, updatable = true, length = 100) 
private String TRANSITION_MATRIX_ID; 

und legte die @Id direkt am ManyToOne und die einführbare und aktualisierbar Attribute entfernen.

@Access(AccessType.FIELD) 
@Id 
@ManyToOne 
@JoinColumn(name = "TRANSITION_MATRIX_ID", referencedColumnName = "ID_TRANSITION_MATRIX") 
private MyLibraryTestEntity sabriEntity; 

Aktualisieren Sie Ihre ID-Klasse entsprechend. Jede frühere Bezugnahme auf TRANSITION_MATRIX_ID sollte durch eine Bezugnahme auf sabriEntity ersetzt werden. Sie verwirren auch @EmbeddedId und @IdClass: Nur Erstere würde Spaltendefinitionen enthalten, während Sie den letzteren Ansatz verwenden.

public class MyLibrarySabriEntityPK implements Serializable { 

    private String sabriEntity; 
    private String RATING_ID_ROW; 
    private String RATING_ID_COL; 
} 

See:

https://en.wikibooks.org/wiki/Java_Persistence/Identity_and_Sequencing#JPA_2.0

Answer 2

Danke an Alan Hay, fand ich das Problem, ich habe die Eigenschaft TRANSITION_MATRIX_ID meiner IdClass zu sabriEntity ändern, und ich all die Annotation dieser Klasse löschen!

Kinder Einheit

@Data 
@Entity 
@IdClass(MyLibrarySabriEntityPK.class) 
@Table(name = "SABRI", schema = "L2S$OWNER", catalog = "") 
public class MyLibrarySabriEntity extends ActionForm { 

@Access(AccessType.FIELD) 
@ManyToOne 
@Id 
@JoinColumn(name = "TRANSITION_MATRIX_ID", referencedColumnName = "ID_TRANSITION_MATRIX") 
private MyLibraryTestEntity sabriEntity; 


@Id 
private String RATING_ID_ROW; 

@Id 
private String RATING_ID_COL; 


@Basic 
@Column(name = "TRANSITION_PROBABILITY", nullable = true, insertable = true, updatable = true, precision = 20) 
private Double TRANSITION_PROBABILITY; 

geordnete Entität

@Data 
@Entity 
@Table(name = "TEST", schema = "L2S$OWNER", catalog = "") 
public class MyLibraryTestEntity extends ActionForm { 

@Access(AccessType.FIELD) 
@OneToMany(mappedBy = "sabriEntity", cascade = CascadeType.PERSIST) 
private final List<MyLibrarySabriEntity> entities = new ArrayList<MyLibrarySabriEntity>(25); 

public void addEntitysabri(MyLibrarySabriEntity entity) { 
    getEntities().add(entity); 
    entity.setSabriEntity(this); 
} 

@Id 
@GeneratedValue(strategy = GenerationType.AUTO, generator = "IdGenerated") 
@GenericGenerator(name = "IdGenerated", strategy = "dao.Identifier") 
@Column(name = "ID_TRANSITION_MATRIX", nullable = false, insertable = false, updatable = false, length = 10) 
private String ID_TRANSITION_MATRIX; 


@Basic 
@Column(name = "REFERENCE", nullable = true, insertable = true, updatable = true, precision = 0) 
private Integer reference; 

PK Klasse

@Data 
public class MyLibrarySabriEntityPK implements Serializable { 
private MyLibraryTestEntity sabriEntity; 
private String RATING_ID_ROW; 
private String RATING_ID_COL; 

public MyLibrarySabriEntityPK() { 
} 

public MyLibrarySabriEntityPK(MyLibraryTestEntity sabriEntity,String RATING_ID_COL,String RATING_ID_ROW){ 
this.sabriEntity=sabriEntity; 
this.RATING_ID_COL = RATING_ID_COL; 
this.RATING_ID_ROW= RATING_ID_ROW; 

}

}