Vergleichen 2 Arrays von Objekten mit Unders die differnce

Question

Ich habe 2 Arrays zu finden, die eine newVal ist und das andere ist origVal

zu definieren

orig:

[ 
{"ListingId":1762276,"Rating":3,"ListPrice":7411828,"PropertyType":"Residential"}, 
{"ListingId":1826692,"Rating":3,"ListPrice":650000,"PropertyType":"Residential"}, 
{"ListingId":1833283,"Rating":4,"ListPrice":950000,"PropertyType":"Residential"}, 
{"ListingId":1832134,"Rating":3,"ListPrice":850000,"PropertyType":"Residential"}, 
{"ListingId":1829932,"Rating":4,"ListPrice":750000,"PropertyType":"Residential"}, 
{"ListingId":1827548,"Rating":5,"ListPrice":650000,"PropertyType":"Residential"} 
] 

neu:

[ 
{"ListingId":1762276,"Rating":2,"ListPrice":7411828,"PropertyType":"Residential"}, 
{"ListingId":1826692,"Rating":3,"ListPrice":650000,"PropertyType":"Residential"}, 
{"ListingId":1833283,"Rating":4,"ListPrice":950000,"PropertyType":"Residential"}, 
{"ListingId":1832134,"Rating":3,"ListPrice":850000,"PropertyType":"Residential"}, 
{"ListingId":1829932,"Rating":4,"ListPrice":750000,"PropertyType":"Residential"}, 
{"ListingId":1827548,"Rating":5,"ListPrice":650000,"PropertyType":"Residential"} 
] 

Wenn ich eine der Bewertungen in "Neu" ändere, wie kann ich diese Änderung erkennen und das geänderte Objekt abrufen?

Es wird immer nur eine Änderung geben, obwohl das nicht wichtig ist.

FYI: Diese Arrays von einem Anjularjs watchcollection produziert werden

$scope.$watchCollection('items', function (new, old) { 

}, true); 

Danke, Stephen

Answer 1

einen Blick auf diese nehmen:

var a = [ 
{"ListingId":1762276,"Rating":3,"ListPrice":7411828,"PropertyType":"Residential"}, 
{"ListingId":1826692,"Rating":3,"ListPrice":650000,"PropertyType":"Residential"}, 
{"ListingId":1833283,"Rating":4,"ListPrice":950000,"PropertyType":"Residential"}, 
{"ListingId":1832134,"Rating":3,"ListPrice":850000,"PropertyType":"Residential"}, 
{"ListingId":1829932,"Rating":4,"ListPrice":750000,"PropertyType":"Residential"}, 
{"ListingId":1827548,"Rating":5,"ListPrice":650000,"PropertyType":"Residential"} 
]; 

var b = [ 
{"ListingId":1762276,"Rating":2,"ListPrice":7411828,"PropertyType":"Residential"}, 
{"ListingId":1826692,"Rating":3,"ListPrice":650000,"PropertyType":"Residential"}, 
{"ListingId":1833283,"Rating":4,"ListPrice":950000,"PropertyType":"Residential"}, 
{"ListingId":1832134,"Rating":3,"ListPrice":850000,"PropertyType":"Residential"}, 
{"ListingId":1829932,"Rating":4,"ListPrice":750000,"PropertyType":"Residential"}, 
{"ListingId":1827548,"Rating":5,"ListPrice":650000,"PropertyType":"Residential"} 
] 

var difference = function(array){ 
    var rest = Array.prototype.concat.apply(Array.prototype, Array.prototype.slice.call(arguments, 1)); 

    var containsEquals = function(obj, target) { 
    if (obj == null) return false; 
    return _.any(obj, function(value) { 
     return _.isEqual(value, target); 
    }); 
    }; 

    return _.filter(array, function(value){ return ! containsEquals(rest, value); }); 
}; 

console.log(JSON.stringify(difference(b, a))); 
> [{"ListingId":1762276,"Rating":2,"ListPrice":7411828,"PropertyType":"Residential"}] 

Der Code auf die ursprüngliche Funktion difference aus Strich basiert, aber es führt einen tiefen Vergleich zwischen Objekten mit isEqual .

Answer 2

Wenn der Auftrag, tun eine einfache Iteration es nicht ändern. Unders bietet die find method für diese Aufgabe:

var changedObj = _.find(newVal, function(obj, index) { 
    return obj.Rating != oldVal[index].Rating; 
}); 

Answer 3

Wie wäre:

const current = [{name:'a'},{name:'b'},{name:'c'}] 
const update = [{name:'x'},{name:'a'},{name:'b'},{name:'f'}] 
const records = current.concat(update); 
const diff = {}; 
diff.in = [] 
diff.out = []; 
records.forEach(item => { 
    if(!current.find(cur => item.name == cur.name))diff.in.push(item) 
    if(!update.find(up => item.name == up.name))diff.out.push(item) 
})