Formatieren von Datum auf MS SQL Server 2008

Question

Ich möchte Daten basierend auf einem Muster wie zum Beispiel 22/01/2015 oder 2016-12-15 formatieren.

Im .NET Framework haben wir DateTime -> ToString() -Methode, die Formate als Argument oder sogar String.Format akzeptiert, die das gleiche tut.

Gibt es eine Funktion auf MS SQL Server 2008, die das Datum basierend auf einem Argumentmuster formatiert?

Answer 1

hatte ich ein ähnliches Problem in SQL 2012 sie eine große Funktion namens Format haben, das Sie in einem Datum und dem Format, das Sie benötigen

SELECT FORMAT(GETDATE(), 'dd/mm/yyy'); 

bringen, gibt es nichts Vergleichbares in SQL Server passieren könnte 2008. Ich habe eine einfache Funktion, um einen ähnlichen Job zu machen, muss es vielleicht optimieren, ist aber keine schlechte Basis.

-- ============================================= 
-- Author:  Luke Mc Redmond 
-- ============================================= 
CREATE FUNCTION [dbo].[FormatDate] 
(
-- Add the parameters for the function here 
@Date DATETIME, 
@Format NVARCHAR(50) 
) 
RETURNS NVARCHAR(50) 
AS 
BEGIN 

    DECLARE @ResultVar nvarchar(50) = UPPER(@Format); 


    DECLARE @d nvarchar(20) = CONVERT(nvarchar(20), DATEPART(day, @Date)); 
    DECLARE @dd nvarchar(20) = CONVERT(nvarchar(20), DATEPART(day, @Date)); 
    DECLARE @day nvarchar(20) = DATENAME(weekday, @Date); 
    DECLARE @ddd nvarchar(20) = DATENAME(weekday, @Date)+' '+CONVERT(nvarchar(5), DATEPART(day, @Date)); 


    DECLARE @m nvarchar(20) = CONVERT(nvarchar, DATEPART(month, @Date)); 
    DECLARE @mm nvarchar(20) = CONVERT(nvarchar, DATEPART(month, @Date)); 
    DECLARE @mmm nvarchar(20) = CONVERT(VARCHAR(3), DATENAME(month, @Date), 100); 
    DECLARE @month nvarchar(20) = DATENAME(month, @Date); 

    DECLARE @y nvarchar(20) = CONVERT(nvarchar, DATEPART(year, @Date)); 
    DECLARE @yy nvarchar(20) = RIGHT(CONVERT(nvarchar, DATEPART(year, GETDATE())),2); 
    DECLARE @yyy nvarchar(20) = CONVERT(nvarchar, DATEPART(year, @Date)); 
    DECLARE @yyyy nvarchar(20) = CONVERT(nvarchar, DATEPART(year, @Date)); 
    DECLARE @year nvarchar(20) = CONVERT(nvarchar, DATEPART(year, @Date)); 

    SELECT @ResultVar = CASE WHEN CHARINDEX('DAY',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS ,'DAY' collate Latin1_General_CS_AS ,@day) 
         WHEN CHARINDEX('DDD',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS ,'DDD' collate Latin1_General_CS_AS ,@ddd) 
         WHEN CHARINDEX('DD',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS ,'DD' collate Latin1_General_CS_AS ,@dd) 
         WHEN CHARINDEX('D',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'D' collate Latin1_General_CS_AS ,@d) END; 

    SELECT @ResultVar = REPLACE(@ResultVar collate Latin1_General_CS_AS,'Monday' collate Latin1_General_CS_AS ,'monday') 

    SELECT @ResultVar = CASE WHEN CHARINDEX('MONTH',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'MONTH' collate Latin1_General_CS_AS,@month) 
         WHEN CHARINDEX('MMM',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS ,'MMM' collate Latin1_General_CS_AS,@mmm) 
         WHEN CHARINDEX('MM',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'MM' collate Latin1_General_CS_AS,@mm) 
         WHEN CHARINDEX('M',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'M' collate Latin1_General_CS_AS,@m) END; 


    SELECT @ResultVar = CASE WHEN CHARINDEX('YEAR',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'YEAR' collate Latin1_General_CS_AS ,@year) 
         WHEN CHARINDEX('YYYY',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'YYYY' collate Latin1_General_CS_AS ,@yyyy) 
         WHEN CHARINDEX('YYY',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS ,'YYY' collate Latin1_General_CS_AS ,@yyy) 
         WHEN CHARINDEX('YY',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS ,'YY' collate Latin1_General_CS_AS ,@yy) 
         WHEN CHARINDEX('Y',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'Y' collate Latin1_General_CS_AS ,@y) END; 

    SELECT @ResultVar = REPLACE(@ResultVar collate Latin1_General_CS_AS,'monday' collate Latin1_General_CS_AS ,'Monday') 

    RETURN @ResultVar 

END; 
GO 

Hoffe, das hilft!

Answer 2

Verwenden Sie die CONVERT-Funktion mit dem Style-Parameter. Es ist alles hier aufgeführt: https://msdn.microsoft.com/en-us/library/ms187928.aspx