oracle sum over() mit where-Klausel

Question

so sollte es aussehen.

eine weitere spezielle Frage. Ich habe folgende Daten und Abfrage:

with helptab as ( 
select '6762' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '6762' as nr, 'A' as sub_val, 0 as sub_nr from dual  
union all 
select '6762' as nr, 'A' as sub_val, 0 as sub_nr from dual  
union all  
select '6762' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '6762' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all  
select '6762' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '6762' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '6763' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '6763' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '6763' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '6763' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '6763' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '6763' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '6763' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '6763' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '6763' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '6835' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '6835' as nr, 'B' as sub_val, 1 as sub_nr from dual 
union all 
select '6835' as nr, 'B' as sub_val, 1 as sub_nr from dual 
union all 
select '6835' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '6835' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'C' as sub_val, 1 as sub_nr from dual 
union all 
select '8904' as nr, 'C' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'C' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'C' as sub_val, 1 as sub_nr from dual 
union all 
select '8904' as nr, 'C' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8904' as nr, 'D' as sub_val, 0 as sub_nr from dual 
union all 
select '8905' as nr, 'B' as sub_val, 1 as sub_nr from dual 
union all 
select '8905' as nr, 'B' as sub_val, 0 as sub_nr from dual 
union all 
select '8905' as nr, 'C' as sub_val, 0 as sub_nr from dual  
union all 
select '8905' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8905' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8905' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8905' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8905' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8905' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8905' as nr, 'A' as sub_val, 0 as sub_nr from dual 
union all 
select '8905' as nr, 'D' as sub_val, 0 as sub_nr from dual) 
select nr, sub_val, sub_nr, count(sub_val) as cnt 
, case when sub_val = 'A' then 0 when sum(count(sub_val)) over(partition by nr) >= 5 then count(sub_val) else 0 end as MoreThan5 
, case when sub_val = 'A' then count(sub_val) when sum(count(sub_val)) over(partition by nr) < 5 then count(sub_val) else 0 end as LessThan5 
from helptab 
group by nr, sub_val, sub_nr 
order by nr, sub_val, sub_nr 

, wie es funktionieren soll:
jede Zeile, wo sub_val ‚A‘ gleich muss auf der LessThan5 Spalte hat zur Folge hat. Alle anderen müssen durch Summe über nr und Sub_val (außer 'A') überprüft werden. wenn weniger als 5, müssen alle Ergebnisse auch auf die LessThan5-Spalte gesetzt werden, andernfalls auf MoreThan5. Ich dachte sum() over (Partition by) ist der richtige Weg, aber es funktioniert nicht richtig.

Answer 1

Wenn ich verstehe alles richtig, zwei kleine Änderungen erforderlich sind:

select nr, sub_val, sub_nr, count(sub_val) as cnt, 
     case 
     when sub_val = 'A' then 0 
     when sum(count(case when sub_val <> 'A' then sub_val end)) -- <-- here 
       over(partition by nr) >= 5 then count(sub_val) 
     else 0 
     end as MoreThan5, 
     case 
     when sub_val = 'A' then count(sub_val) 
     when sum(count(case when sub_val <> 'A' then sub_val end)) -- <-- and here 
       over(partition by nr) < 5 then count(sub_val) 
     else 0 
     end as LessThan5 
    from helptab 
group by nr, sub_val, sub_nr 
order by nr, sub_val, sub_nr