Methoden aufrufen C++, Neuling ... Fehler kompilieren BITTE HELFEN

Question

mit dem folgenden Programm Ich bekomme eine Menge Kompilierungsfehler, wenn ich es versuche und kompiliere es. Ich denke, sie haben etwas zu tun mit Methode aufrufen. Ich bin nicht vertraut mit C++ und weiß nicht, was sie verursacht. Kann jemand helfen? Hier ist der Quellcode:

#include <iostream> 
using namespace std; 
//getting the greatest common divisor to help reduce fractions 
int GDC(int x, int y) 
{ 
    int t; 
    while (y!=0) 
    { 
     t=y; 
     y=x%y; 
     x=t; 
    } 
    return x; 
} 

//constructing a RationalNumber wit a numerator and a denominator as seperate elements. 
//it also reduces the fraction as well as show them. 
//prevents 0 in the denominator as well as avoid negative denominators 
class RationalNumber 
{ 
    public: 
     RationalNumber(int num=0, int denom=0) 
     { 
      numerator=num; 
      denominator=denom; 
     } 
     void show() 
     { 
      { 
       cout << "(" << numerator <<"/"; 
       cout << denominator << ")"; 
      } 
     } 
     void reduce() 
     { 
      int reduction; 
      reduction= GCD(numerator, denominator); 
      numerator=numerator/reduction; 
      denominator=denominator/reduction; 

      if(denominator == 0) 
      { 
       cout << "Cannot compute with 0 denominator "; 
      } 
      if(denominator < 0) 
      { 
       cout << "Cannot compute negative demoninators "; 
      } 
      else 
      { 
       //simplifies fraction to a whole number when denominator is 1 
       if(denominator == 1) 
       { 
        cout << "(" << numerator <<")"; 
       } 
       else 
       { 
        cout << "(" << numerator <<"/"; 
        cout << denominator << ")"; 
       } 
      } 
     } 
     RationalNumber operator+(RationalNumber op2); 
     RationalNumber operator-(RationalNumber op2); 
     RationalNumber operator*(RationalNumber op2); 
     RationalNumber operator/(RationalNumber op2); 
     RationalNumber operator++(); 

    private: 
     double numerator, denominator; 
}; 

void Accept(int n) 
{ 
    if(n<0) 
    { 
     cout << "Cannot have negatice denominators: "; 
    } 
    else if (n == 0) 
     cout << "Cannot have zero in the denominator: "; 
} 

//Division 
RationalNumber RationalNumer::operator/(RationalNumber op2) 
{ 
    RationalNumber temp; 
    int reduction; 
    temp.numerator=(numerator*op2.denominator); 
    temp.denominator=denominator*op2.numerator; 
    cout << "Division:  "; 
    return temp; 
} 

//Subtraction 
RationalNumber RationalNumer::operator-(RationalNumber op2) 
{ 
    RationalNumber temp; 
    int reduction; 
    temp.numerator=(numerator*op2.denominator)-(op2.numerator*denominator); 
    temp.denominator=op2.denominator* denominator; 
    cout << "Subtraction:  "; 
    return temp; 
} 

//Multiplication 
RationalNumber RationalNumer::operator*(RationalNumber op2) 
{ 
    RationalNumber temp; 
    temp.numerator=(op2.numerator*numerator); 
    temp.denominator=op2.denominator* denominator; 
    cout << "Multiplication:  "; 
    return temp; 
} 

//Addition 
RationalNumber RationalNumer::operator+(RationalNumber op2) 
{ 
    RationalNumber temp; 
    temp.numerator=(op2.numerator*denominator) + ((numerator)*(op2.denominator)); 
    temp.denominator=op2.denominator* denominator; 
    cout << "Addition:  "; 
    return temp; 
} 

RationalNumber RationalNumer::operator++() 
{ 
    numerator++; 
    denominator++; 
    return *this; 
} 


void getFraction(int &x, int &y, int &z, int &t) 
{ 
    cout << "First Fraction: "; 
    cout << "\n"; 
    cout << "numerator: "; 
    cin >> x; 

    do 
    { 
     cout << "denominator: "; 
     cin >> y; 
     Accept(y); 
     cout << "\n"; 
     cout << endl; 
    } 
    while(y <=0); 

    cout << "Second Fraction: "; 
    cout << "\n"; 
    cout << "numerator: "; 
    cin >> z; 
    do 
    { 
     cout << "denominator: "; 
     cin >> t; 
     Accept(t); 
     cout << "\n"; 
     cout << endl; 
    } 
    while(t <=0); 
} 

void aftermath(int &x, int &y, int &z, int &t) 
{ 
    RationalNumber obA, obS, obM, obD, ob2(x,y), ob3(z,t); 
    char Math; 
    cout << "Enter sign (+,-,*,/): "; 
    cin >> Math; 
    if(Math == '+') 
    { 
     obA=ob2+ob3; 
     obA.reduce(); 
     cout << "\n"; 
    } 
    else if(Math == '-') 
    { 
     obS=ob2-ob3; 
     obS.reduce(); 
     cout << "\n\n"; 
    } 
    else if(Math == '*') 
    { 
     obM=ob2*ob3; 
     obM.reduce(); 
     cout << "\n\n"; 
    } 
    else if(Math == '/') 
    { 
     obD=ob2/ob3; 
     obD.reduce(); 
     cout << "\n\n"; 
    } 
    else 
     cout << "Invalid sign"; 
} 

int main() 
{ 
    char answer; 
    do 
    { 
     int x,y,z,t = 0; 
     getFraction(x,y,z,t); 
     RationalNumber obA, obS, obM, obD, ob2(x,y), ob3(z,t); 

     ob2.show(); 
     cout <<" "; 
     ob3.show(); 
     cout << "\n\n"; 
     aftermath(x,y,z,t); 
     cout << "\n\n"; 
     cout << "Create another fraction? - y or n? "; 
     cin >> answer; 
     cout << "\n"; 
    } 
    while((answer == 'y')); 

    if((answer != 'y')) 
    { 
     cout << "GOOD-BYE "; 
    } 
    return 0; 
} 

und hier werden die kompilieren Fehler:

g++ -o Math math.cpp 
math.cpp: In member function 'void RationalNumber::reduce()': 
math.cpp:37: error: 'GCD' was not declared in this scope 
math.cpp: In function 'void getFraction(int&, int&, int&, int&)': 
math.cpp:136: error: invalid operands of types '<unresolved overloaded function type>' and 'const char [2]' to binary 'operator<<' 
math.cpp:151: error: invalid operands of types '<unresolved overloaded function type>' and 'const char [2]' to binary 'operator<<' 

Vielen Dank Jungs

Answer 1

(Hinweis: Kyle die Ausgabe aktualisiert hat, da ich die Antwort geschrieben, so dass einige davon fehlt der richtige Kontext.)

Erster Fehler: Sie rufen "GCD", aber Ihre Funktion heißt "GDC".

Zweiter Fehler: "RationalNumer" nicht "RationalNumber".

Die meisten oder alle anderen Fehler werden verschwinden, wenn Sie den zweiten Fehler an allen Stellen beheben, an denen er auftritt (und es gibt fünf davon - suchen Sie nach "RationalNumer").

Neuer Fehler in der aktualisierten Ausgabe - ein weiterer Tippfehler: count << "\n"; sollte cout << "\n"; sein.

Zwei Stücke allgemeine Ratschläge:

• lesen die Fehlermeldungen. 8-) Oft werden sie als undurchdringlicher Jargon erscheinen oder einfach nur lügen, aber oft ist die Antwort wirklich da drin.

• Sorgen Sie sich immer nur um den ersten Fehler. Mehr als oft nicht, wenn das behoben wird, werden einige oder alle anderen verschwinden.