Bilder anzeigen RSS-Feed in Objective C mit

Question

ich Bilder anzuzeigen, aus der URL

RSS Feed

Ich verwende Tabelle View-Controller in meinem Ziel c project..I der Lage ist anzuzeigen Text und Links perfekt möge aber nicht in der Lage Bilder von der Feed-uRL anzuzeigen

ich verwende den folgenden Code

**TableViewController.h** 
#import <UIKit/UIKit.h> 

@interface TableViewController : UITableViewController <NSXMLParserDelegate> 

@property (strong, nonatomic) IBOutlet UITableView *TableView; 

@end 

TableViewController.m

#import "TableViewController.h" 
#import "ViewController.h" 

@interface TableViewController(){ 

    NSXMLParser *parser; 
    NSMutableArray *feeds; 
    NSMutableDictionary *item; 
    NSMutableString *title; 
    NSMutableString *link; 
    NSString *element; 
    NSString *imageType; 
    NSString *imageUrl; 
} 

@end 

@implementation TableViewController 


- (void)viewDidLoad { 
    [super viewDidLoad]; 

    feeds=[[NSMutableArray alloc ] init]; 
     NSURL *url = [NSURL URLWithString:@"https://www.nasa.gov/rss/dyn/breaking_news.rss"]; 
    parser = [[NSXMLParser alloc] initWithContentsOfURL:url]; 
    [parser setDelegate:self]; 
    [parser setShouldResolveExternalEntities:NO]; 
    [parser parse]; 


} 

- (void)didReceiveMemoryWarning { 
    [super didReceiveMemoryWarning]; 
    // Dispose of any resources that can be recreated. 
} 

#pragma mark - Table view data source 

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { 



    return 1; 
} 

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { 



    return feeds.count; 
} 


- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { 
    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"Cell" forIndexPath:indexPath]; 
    cell.textLabel.text = [[feeds objectAtIndex:indexPath.row] objectForKey:@"title"]; 





    // cell.imageView.image= [[feeds objectAtIndex:indexPath.row] objectForKey:@"title"]; 

    return cell; 
} 

-(void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName attributes:(NSDictionary *)attributeDict { 

    element = elementName; 

    if ([element isEqualToString:@"item"]) { 

     item = [[NSMutableDictionary alloc] init]; 
     title = [[NSMutableString alloc] init]; 
     link = [[NSMutableString alloc] init]; 
    } 


    if ([element isEqualToString:@"enclosure"]) { 
     imageType = [attributeDict objectForKey:@"type"]; 
     imageUrl = [attributeDict objectForKey:@"url"]; 

    } 


} 

-(void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName { 

    if ([elementName isEqualToString:@"item"]) { 

     [item setObject:title forKey:@"title"]; 
     [item setObject:link forKey:@"link"]; 


     [item setObject:imageType forKey:@"imageType"]; 
     [item setObject:imageUrl forKey:@"imageUrl"]; 


     [feeds addObject:[item copy]]; 

    } 

} 

-(void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string { 

    if ([element isEqualToString:@"title"]) { 
     [title appendString:string]; 
    } else if ([element isEqualToString:@"link"]) { 
     [link appendString:string]; 
    } 
} 

-(void)parserDidEndDocument:(NSXMLParser *)parser { 

    [self.tableView reloadData]; 
} 


-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender { 

    if ([[segue identifier] isEqualToString:@"showDetail"]) { 
     NSIndexPath *indexPath = [self.tableView indexPathForSelectedRow]; 
     NSString *string = [feeds[indexPath.row] objectForKey:@"link"]; 
     [[segue destinationViewController] setUrl:string]; 
    } 

} 




@end 

Bitte helfen Sie mir Bilder, die ich mit this.thanks

Answer 1

Verwenden Sie diese Art und Weise stecke anzuzeigen:

if (cell == nil) 

    { 

     cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:@"identifier"]; 
     UIImageview imgView = [[UIImageView alloc] initWithFrame:CGRectMake(150, 0, 48, 48)]; 
imgView.tag = 100; 


//ssame way create a label 
    UILabel titleLabel = [[UILabel alloc] initWithFrame:CGRectMake(0, 0, 100, 40)]; 
titlelabel.tag = 102 
[cell.contentview addsubview:imgview]; 
[cell.contentview addsubview:titlelabel]; 
    } 

    UIImageview mImgView = (uiimageview *)[cell viewwithtag:100]; 
UILabel mLabel = (uilabel*)cell viewwithtag:102]; 

//set data 
mlabel = //your label 
mimgviw.imge = imageurl 

Answer 2

Setzen Sie einfach folgende Zeile zu UITableViewCell

NSString *imgUrl = [[feeds objectAtIndex:indexPath.row] objectForKey:@"imageUrl"]; 
    UIImage *image = [UIImage imageWithData:[NSData dataWithContentsOfURL:[NSURL URLWithString:imgUrl]]]; 

    cell.imageView.image = image;