Rechner - Power Button

Question

Ich habe versucht, einen Rechner mit tkinter zu programmieren, und bisher habe ich alle vier Grundoperationen, Addition, Subtraktion, Multiplikation und Division gemacht. Ich habe auch einen klaren Knopf und Knöpfe für alle Nummern gemacht. Jetzt möchte ich einen "Power" Button machen und ich weiß nicht wie. Wenn ich es in den Taschenrechner gebe, ist die Antwort nicht die richtige Antwort. Weiß jemand, wie man die Power-Taste funktioniert und nicht die anderen Tasten, wenn ich das tue?

Der Code ist da unten, so dass Sie sehen können, was ich getan habe.

#calculator with tkinter 
import sys 
from tkinter import * 
from tkinter import messagebox 
from tkinter import filedialog 

a = Tk() 

frame = Frame(a) 
frame.pack() 

a.title('Calculator') 

def clear(): 
    mbox = textDisplay.delete(len(textDisplay.get())-1, END) 
    return 
def set_text(text): 
    textDisplay.insert(END, text) 
    return 

def clear_all(): 
    textDisplay.delete(0, END) 
    return 

def equals(): 
    try: 
     result = eval(textDisplay.get()) 
    except: 
     messagebox.showerror(message = 'Invalid Answer') 
    clear_all() 
    set_text(result) 





box = StringVar() 

topframe = Frame(a) 
topframe.pack(side = TOP) 

textDisplay = Entry(frame, textvariable = box, bd = 20, insertwidth = 1, font = 30) 
textDisplay.pack(side = TOP) 

button1 = Button(topframe, padx = 16, pady = 16, bd = 8, text = '1', command = lambda:set_text('1')) 
button1.pack(side = LEFT) 

button2 = Button(topframe, padx = 16, pady = 16, bd = 8, text = '2', command = lambda:set_text('2')) 
button2.pack(side = LEFT) 

button3 = Button(topframe, padx = 16, pady = 16, bd = 8, text = '3', command = lambda:set_text('3')) 
button3.pack(side = LEFT) 

plus = Button(topframe, padx = 16, pady = 16, bd = 8, text = '+', command = lambda:set_text('+')) 
plus.pack(side = LEFT) 

middleframe = Frame(a) 
middleframe.pack(side = TOP) 

button4 = Button(middleframe, padx = 16, pady = 16, bd = 8, text = '4', command = lambda:set_text('4')) 
button4.pack(side = LEFT) 

button5 = Button(middleframe, padx = 16, pady = 16, bd = 8, text = '5', command = lambda:set_text('5')) 
button5.pack(side = LEFT) 

button6 = Button(middleframe, padx = 16, pady = 16, bd = 8, text = '6', command = lambda:set_text('6')) 
button6.pack(side = LEFT) 

minus = Button(middleframe, padx = 16, pady = 16, bd = 8, text = '-', command = lambda:set_text('-')) 
minus.pack(side = LEFT) 

bottomframe = Frame(a) 
bottomframe.pack(side = TOP) 

button7 = Button(bottomframe, padx = 16, pady = 16, bd = 8, text = '7', command = lambda:set_text('7')) 
button7.pack(side = LEFT) 

button8 = Button(bottomframe, padx = 16, pady = 16, bd = 8, text = '8', command = lambda:set_text('8')) 
button8.pack(side = LEFT) 

button9 = Button(bottomframe, padx = 16, pady = 16, bd = 8, text = '9', command = lambda:set_text('9')) 
button9.pack(side = LEFT) 

times = Button(bottomframe, padx = 16, pady = 16, bd = 8, text = 'x', command = lambda:set_text('*')) 
times.pack(side = LEFT) 

morebottom = Frame(a) 
morebottom.pack(side = TOP) 

equals = Button(morebottom, padx = 16, pady = 16, bd = 8, text = '=', command = equals) 
equals.pack(side = LEFT) 

button0 = Button(morebottom, padx = 16, pady = 16, bd = 8, text = '0', command = lambda:set_text('0')) 
button0.pack(side = LEFT) 

clearbu = Button(morebottom, padx = 16, pady = 16, bd = 8, text = 'C', command = clear) 
clearbu.pack(side = LEFT) 

div = Button(morebottom, padx = 16, pady = 16, bd = 8, text = '/', command = lambda:set_text('/')) 
div.pack(side = LEFT) 

evenmore = Frame(a) 
evenmore.pack(side = TOP) 

cebut = Button(evenmore, padx = 16, pady = 16, bd = 8, text = 'CE', command = clear_all) 
cebut.pack(side = LEFT) 

decimal = Button(evenmore, padx = 16, pady = 16, bd = 8, text = '.', command = lambda:set_text('.')) 
decimal.pack(side = LEFT) 

power = Button(evenmore, padx = 16, pady = 16, bd = 8, text = '^', command = lambda:set_text('^')) 
power.pack(side = LEFT) 

a.mainloop 

Answer 1

^ ist xor, verwenden ** stattdessen eine Zahl auf eine Leistung in Python zu erhöhen.

die endgültige ^ mit ** in power = Button(evenmore, padx = 16, pady = 16, bd = 8, text = '^', command = lambda:set_text('^')) Ersetzen geben Sie das richtige Ergebnis, aber es wird ** im Display Ihres Rechners angezeigt werden soll. Stattdessen können Sie result = eval(textDisplay.get()) durch result = eval(textDisplay.get().replace('^', '**')) ersetzen, so dass die erwarteten Symbole angezeigt werden, aber die Antwort wird korrekt sein.