zwei SELECT-Anweisungen in mysql-Tabelle einfügen

Question

hi kann mir jemand sagen, wie man diese beiden Select-Anweisungen in eine Tabelle einfügt.

INSERT INTO test(Team, GamesPlayedHome, GoalsScorredHome, GoalsAcceptedHome, RedCardGotHome, AvarageGoalsScorredHome, AvarageGoalsAcceptedHome, GamesPlayedAway, GoalsScorredAway, GoalsAcceptedAway, RedCardGotAway, AvarageGoalsScorredAway, AvarageGoalsAcceptedAway) 

SELECT HomeTeam As Team, COUNT(HomeTeam) AS GamesPlayedHome, SUM(HomeGoals) AS GoalsScorredHome, SUM(AwayGoals) AS GoalsAcceptedHome, SUM(HomeRedCards) AS RedCardGotHome, 
SUM(HomeGoals)/COUNT(HomeTeam) AS AvarageGoalsScorredHome, SUM(AwayGoals)/COUNT(HomeTeam) AS AvarageGoalsAcceptedHome 
FROM GetHistoricMatchesByLeagueAndDateInterval GROUP BY HomeTeam ORDER BY HomeTeam ASC 

SELECT COUNT(AwayTeam) AS GamesPlayedAway, SUM(AwayGoals) AS GoalsScorredAway, SUM(HomeGoals) AS GoalsAcceptedAway, SUM(AwayRedCards) AS RedCardGotAway, 
SUM(HomeGoals)/COUNT(AwayTeam) AS AvarageGoalsScorredAway, SUM(AwayGoals)/COUNT(AwayTeam) AS AvarageGoalsAcceptedAway 
FROM GetHistoricMatchesByLeagueAndDateInterval GROUP BY AwayTeam ORDER BY AwayTeam ASC 

Ich habe diese tryed

<?php 
include("conf.php"); 
$query = "INSERT INTO test(Team, GamesPlayedHome, GoalsScorredHome, GoalsAcceptedHome, RedCardGotHome, AvarageGoalsScorredHome, AvarageGoalsAcceptedHome, GamesPlayedAway, GoalsScorredAway, GoalsAcceptedAway, RedCardGotAway, AvarageGoalsScorredAway, AvarageGoalsAcceptedAway) 
(SELECT HomeTeam As Team, COUNT(HomeTeam) AS GamesPlayedHome, SUM(HomeGoals) AS GoalsScorredHome, SUM(AwayGoals) AS GoalsAcceptedHome, SUM(HomeRedCards) AS RedCardGotHome, 
SUM(HomeGoals)/COUNT(HomeTeam) AS AvarageGoalsScorredHome, SUM(AwayGoals)/COUNT(HomeTeam) AS AvarageGoalsAcceptedHome 
FROM GetHistoricMatchesByLeagueAndDateInterval GROUP BY HomeTeam ORDER BY HomeTeam ASC) 
UNION ALL 
(SELECT COUNT(AwayTeam) AS GamesPlayedAway, SUM(AwayGoals) AS GoalsScorredAway, SUM(HomeGoals) AS GoalsAcceptedAway, SUM(AwayRedCards) AS RedCardGotAway, 
SUM(HomeGoals)/COUNT(AwayTeam) AS AvarageGoalsScorredAway, SUM(AwayGoals)/COUNT(AwayTeam) AS AvarageGoalsAcceptedAway 
FROM GetHistoricMatchesByLeagueAndDateInterval GROUP BY AwayTeam ORDER BY AwayTeam ASC) 
"; 
$data= mysqli_query($conn,$query) or die(mysqli_error($conn)); 
while($row = mysqli_fetch_assoc($data)){ 
    foreach($row as $cname => $cvalue){ 
     print "$cname: $cvalue\t"; 
    } 
    print "\r\n"; 
} 
?> 

ich diesen Fehler bekommen, wenn ich es laufen

Spaltenanzahl in Zeile nicht Zählwert entsprechen 1

I auch mit Multi-Abfrage

versucht

<?php 
include("conf.php"); 
//QUERY 1 
$query = "INSERT INTO test(Team, GamesPlayedHome, GoalsScorredHome, GoalsAcceptedHome, RedCardGotHome, AvarageGoalsScorredHome, AvarageGoalsAcceptedHome) 
SELECT HomeTeam As Team, COUNT(HomeTeam) AS GamesPlayedHome, SUM(HomeGoals) AS GoalsScorredHome, SUM(AwayGoals) AS GoalsAcceptedHome, SUM(HomeRedCards) AS RedCardGotHome, 
SUM(HomeGoals)/COUNT(HomeTeam) AS AvarageGoalsScorredHome, SUM(AwayGoals)/COUNT(HomeTeam) AS AvarageGoalsAcceptedHome 
FROM GetHistoricMatchesByLeagueAndDateInterval GROUP BY HomeTeam ORDER BY HomeTeam ASC;"; 
//QUERY 2 
$query .= "INSERT INTO test(GamesPlayedAway, GoalsScorredAway, GoalsAcceptedAway, RedCardGotAway, AvarageGoalsScorredAway, AvarageGoalsAcceptedAway) 
SELECT COUNT(AwayTeam) AS GamesPlayedAway, SUM(AwayGoals) AS GoalsScorredAway, SUM(HomeGoals) AS GoalsAcceptedAway, SUM(AwayRedCards) AS RedCardGotAway, 
SUM(HomeGoals)/COUNT(AwayTeam) AS AvarageGoalsScorredAway, SUM(AwayGoals)/COUNT(AwayTeam) AS AvarageGoalsAcceptedAway 
FROM GetHistoricMatchesByLeagueAndDateInterval GROUP BY AwayTeam ORDER BY AwayTeam ASC"; 

/* execute multi query */ 
if ($conn->multi_query($query)) { 
    do { 
     /* store first result set */ 
     if ($result = $conn->store_result()) { 
      while ($row = $result->fetch_row()) { 
       printf("%s\n", $row[0]); 
      } 
      $result->free(); 
     } 
     /* print divider */ 
     if ($conn->more_results()) { 
      printf("-----------------\n"); 
     } 
    } while ($conn->next_result()); 
} 

/* close connection */ 
$conn->close(); 
?> 

Wenn ich diesen Code ausführen es die Daten einfügt, aber die zweite Abfrage fügt auch leere Zeilen

Bitte etwas Hilfe

Last Code

<?php 
include("conf.php"); 
$query = "SELECT querya.Team, GamesPlayedHome, GoalsScorredHome, GoalsAcceptedHome, RedCardGotHome, AvarageGoalsScorredHome, AvarageGoalsAcceptedHome, GamesPlayedAway, GoalsScorredAway, GoalsAcceptedAway, RedCardGotAway, AvarageGoalsScorredAway, AvarageGoalsAcceptedAway 
from 
(SELECT HomeTeam As Team, COUNT(HomeTeam) AS GamesPlayedHome, SUM(HomeGoals) AS GoalsScorredHome, SUM(AwayGoals) AS GoalsAcceptedHome, SUM(HomeRedCards) AS RedCardGotHome, 
SUM(HomeGoals)/COUNT(HomeTeam) AS AvarageGoalsScorredHome, SUM(AwayGoals)/COUNT(HomeTeam) AS AvarageGoalsAcceptedHome 
FROM GetHistoricMatchesByLeagueAndDateInterval GROUP BY HomeTeam ORDER BY HomeTeam ASC) 
querya inner join 
(SELECT AwayTeam As Team, COUNT(AwayTeam) AS GamesPlayedAway, SUM(AwayGoals) AS GoalsScorredAway, SUM(HomeGoals) AS GoalsAcceptedAway, SUM(AwayRedCards) AS RedCardGotAway, 
SUM(HomeGoals)/COUNT(AwayTeam) AS AvarageGoalsScorredAway, SUM(AwayGoals)/COUNT(AwayTeam) AS AvarageGoalsAcceptedAway 
FROM GetHistoricMatchesByLeagueAndDateInterval GROUP BY AwayTeam ORDER BY AwayTeam ASC) 
queryb on querya.Team = queryb.Team"; 
$data= mysqli_query($conn,$query) or die(mysqli_error($conn)); 
while($row = mysqli_fetch_assoc($data)){ 
    foreach($row as $cname => $cvalue){ 
     print "$cname: $cvalue\t"; 
    } 
    print "\r\n"; 
} 
?> 

Answer 1

Dies ist Pseudo-Code im besten Fall, aber es ist ein Versuch.

Select (put all fields in here) 
from (put first query in its entirey here) querya 
inner join (put second query here, you will need to modify so it has a 'team' column) queryb 
on querya.team = queryb.team 

Erhalten Sie die Idee? Union ist der falsche Begriff für das, was Sie versuchen ... Join ist, was Sie suchen.

Sie haben:

"SELECT (Team, GamesPlayedHome, GoalsScorredHome, GoalsAcceptedHome, RedCardGotHome, AvarageGoalsScorredHome, AvarageGoalsAcceptedHome, GamesPlayedAway, GoalsScorredAway, GoalsAcceptedAway, RedCardGotAway, AvarageGoalsScorredAway, AvarageGoalsAcceptedAway) 
from ... 

Die Klammern nicht benötigt werden.

"SELECT Team, GamesPlayedHome, GoalsScorredHome, GoalsAcceptedHome, RedCardGotHome, AvarageGoalsScorredHome, AvarageGoalsAcceptedHome, GamesPlayedAway, GoalsScorredAway, GoalsAcceptedAway, RedCardGotAway, AvarageGoalsScorredAway, AvarageGoalsAcceptedAway 
from ... 

Ich edited Ihre Frage, verwenden Sie es von dort.

Answer 2

Das sieht aus wie es sollte "funktionieren" (wie in, nicht aus Fehler), aber es kann nicht sein, was Sie wollen und/oder ich kann mich irren ...

INSERT INTO test 
(Team 
, GamesPlayedHome 
, GoalsScorredHome 
, GoalsAcceptedHome 
, RedCardGotHome 
, AvarageGoalsScorredHome 
, AvarageGoalsAcceptedHome 
, GamesPlayedAway 
, GoalsScorredAway 
, GoalsAcceptedAway 
, RedCardGotAway 
, AvarageGoalsScorredAway 
, AvarageGoalsAcceptedAway 
) 
SELECT HomeTeam 
    , COUNT(HomeTeam) 
    , SUM(HomeGoals) 
    , SUM(AwayGoals) 
    , SUM(HomeRedCards) 
    , SUM(HomeGoals)/COUNT(HomeTeam) 
    , SUM(AwayGoals)/COUNT(HomeTeam) 
    FROM GetHistoricMatchesByLeagueAndDateInterval 
GROUP 
    BY HomeTeam 
UNION 
    ALL 
SELECT COUNT(AwayTeam) 
    , SUM(AwayGoals) 
    , SUM(HomeGoals) 
    , SUM(AwayRedCards) 
    , SUM(HomeGoals)/COUNT(AwayTeam) 
    , SUM(AwayGoals)/COUNT(AwayTeam) 
    FROM GetHistoricMatchesByLeagueAndDateInterval 
GROUP 
    BY AwayTeam 

(Ihre Schreibweise ist scheußlich, BTW)