Linux Start-up-Skript in Systemd

Question

Kann ich tun Dies starten Dienst unten, gibt es keine Fehler zeigen einmal ausgeführt, aber das Server-Skript unten läuft nicht!

ln /lib/systemd/aquarium.service aquarium.service 
systemctl daemon-reload 
systemctl enable aquarium.service 
systemctl start aquarium.service 

dank

aquarium.service:

[Unit] 
Description=Start aquarium server 

[Service] 
WorkingDirectory=/home/root/python/code/aquarium/ 
ExecStart=/bin/bash server.* start 
KillMode=process 

[Install] 
WantedBy=multi-user.target 

hier ist das server.sh Skript

#!/bin/bash 

PID="" 

function get_pid { 
    PID=`pidof python ./udpthread.py` 
} 

function stop { 
    get_pid 
    if [ -z $PID ]; then 
     echo "server is not running." 
     exit 1 
    else 
     echo -n "Stopping server.." 
     kill -9 $PID 
     sleep 1 
     echo ".. Done." 
    fi 
} 


function start { 
    get_pid 
    if [ -z $PID ]; then 
     echo "Starting server.." 
     ./udpthread.py & 
     get_pid 
     echo "Done. PID=$PID" 
    else 
     echo "server is already running, PID=$PID" 
    fi 
} 

function restart { 
    echo "Restarting server.." 
    get_pid 
    if [ -z $PID ]; then 
     start 
    else 
     stop 
     sleep 5 
     start 
    fi 
} 


function status { 
    get_pid 
    if [ -z $PID ]; then 
     echo "Server is not running." 
     exit 1 
    else 
     echo "Server is running, PID=$PID" 
    fi 
} 

case "$1" in 
    start) 
     start 
    ;; 
    stop) 
     stop 
    ;; 
    restart) 
     restart 
    ;; 
    status) 
     status 
    ;; 
    *) 
     echo "Usage: $0 {start|stop|restart|status}" 
esac 

Answer 1

mit "Type = Forking" Try and Nutzung vollständiger Dateiname

[Unit] 
Description=Start aquarium server 

[Service] 
WorkingDirectory=/home/root/python/code/aquarium/ 
Type=forking 
ExecStart=/bin/bash server.sh start 
KillMode=process 

[Install] 
WantedBy=multi-user.target 

wenn es nicht funktionieren, senden Sie Ausgabe dieses Befehls:

# journalctl -u aquarium.service